What are the solutions to the equation 5x^2+3x=-1 ?

The solutions to the equation 5x^2+3x=-1 are x=-3/10+i(sqrt(11))/(10),x=-3/10-i(sqrt(11))/(10)

Find the zeros of 5x^2+3x=-1

The zeros of 5x^2+3x=-1 are x=-3/10+i(sqrt(11))/(10),x=-3/10-i(sqrt(11))/(10)

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5 x^{2} + 3 x = - 1

x = - \frac{3}{10} + i \frac{11}{10}, x = - \frac{3}{10} - i \frac{11}{10}

Solution steps

5 x^{2} + 3 x = - 1

Move

1

to the left side

5 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

3^{2} - 4 \cdot 5 \cdot 1 : 11 i

x_{1, 2} = \frac{- 3 \pm 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 11 i}{2 \cdot 5}, x_{2} = \frac{- 3 - 11 i}{2 \cdot 5}

x = \frac{- 3 + 11 i}{2 \cdot 5} : - \frac{3}{10} + i \frac{11}{10}

x = \frac{- 3 - 11 i}{2 \cdot 5} : - \frac{3}{10} - i \frac{11}{10}

The solutions to the quadratic equation are:

x = - \frac{3}{10} + i \frac{11}{10}, x = - \frac{3}{10} - i \frac{11}{10}

\frac{x}{- 9} \geq 3

12 x^{2} - 4 = 22 x

x (x + 7)^{2} (x - 1) \leq 0

\frac{40 y ^{2}}{5 x y}

4 \leq - 3 v + 16

What are the solutions to the equation 5x^2+3x=-1 ?
The solutions to the equation 5x^2+3x=-1 are x=-3/10+i(sqrt(11))/(10),x=-3/10-i(sqrt(11))/(10)
Find the zeros of 5x^2+3x=-1
The zeros of 5x^2+3x=-1 are x=-3/10+i(sqrt(11))/(10),x=-3/10-i(sqrt(11))/(10)