What are the solutions to the equation 10x^2-4x+10=0 ?

The solutions to the equation 10x^2-4x+10=0 are x= 1/5+i(2sqrt(6))/5 ,x= 1/5-i(2sqrt(6))/5

Find the zeros of 10x^2-4x+10=0

The zeros of 10x^2-4x+10=0 are x= 1/5+i(2sqrt(6))/5 ,x= 1/5-i(2sqrt(6))/5

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10 x^{2} - 4 x + 10 = 0

x = \frac{1}{5} + i \frac{2 6}{5}, x = \frac{1}{5} - i \frac{2 6}{5}

Solution steps

10 x^{2} - 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

(- 4)^{2} - 4 \cdot 10 \cdot 10 : 86 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 6 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 6 i}{2 \cdot 10}, x_{2} = \frac{- ( - 4 ) - 8 6 i}{2 \cdot 10}

x = \frac{- ( - 4 ) + 8 6 i}{2 \cdot 10} : \frac{1}{5} + i \frac{2 6}{5}

x = \frac{- ( - 4 ) - 8 6 i}{2 \cdot 10} : \frac{1}{5} - i \frac{2 6}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{2 6}{5}, x = \frac{1}{5} - i \frac{2 6}{5}

8 x + (- 5 x) = 27

3 x^{2} + 18 x + 15

3 - 2 x + 4 [3 + 5 (x + 1)] = 10 x - 7

100 a^{2} b^{2} - 20 ab + 1

2 n + 2 \geq 10

What are the solutions to the equation 10x^2-4x+10=0 ?
The solutions to the equation 10x^2-4x+10=0 are x= 1/5+i(2sqrt(6))/5 ,x= 1/5-i(2sqrt(6))/5
Find the zeros of 10x^2-4x+10=0
The zeros of 10x^2-4x+10=0 are x= 1/5+i(2sqrt(6))/5 ,x= 1/5-i(2sqrt(6))/5