What are the solutions to the equation t^2+3t+2=0 ?

The solutions to the equation t^2+3t+2=0 are t=-1,t=-2

Find the zeros of t^2+3t+2=0

The zeros of t^2+3t+2=0 are t=-1,t=-2

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t^{2} + 3 t + 2 = 0

t = - 1, t = - 2

Solution steps

t^{2} + 3 t + 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

t_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 3 + 1}{2 \cdot 1}, t_{2} = \frac{- 3 - 1}{2 \cdot 1}

t = \frac{- 3 + 1}{2 \cdot 1} : - 1

t = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

t = - 1, t = - 2

(- 1)^{n} (- 1)^{n}

\frac{1}{5} + \frac{1}{6}

6 y^{2} + 11 y - 35

- 2 (u + 6) - 6 u = 4 (u + 3)

3 x^{2} - 5 x - 11 = 0

What are the solutions to the equation t^2+3t+2=0 ?
The solutions to the equation t^2+3t+2=0 are t=-1,t=-2
Find the zeros of t^2+3t+2=0
The zeros of t^2+3t+2=0 are t=-1,t=-2