What are the solutions to the equation 8m^2-2m-7=0 ?

The solutions to the equation 8m^2-2m-7=0 are m=(1+sqrt(57))/8 ,m=(1-sqrt(57))/8

Find the zeros of 8m^2-2m-7=0

The zeros of 8m^2-2m-7=0 are m=(1+sqrt(57))/8 ,m=(1-sqrt(57))/8

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8 m^{2} - 2 m - 7 = 0

m = \frac{1 + 57}{8}, m = \frac{1 - 57}{8}

Decimal Notation

m = 1.06872 \dots, m = - 0.81872 \dots

Solution steps

8 m^{2} - 2 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 7 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 7) = 257

m_{1, 2} = \frac{- ( - 2 ) \pm 2 57}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 57}{2 \cdot 8}, m_{2} = \frac{- ( - 2 ) - 2 57}{2 \cdot 8}

m = \frac{- ( - 2 ) + 2 57}{2 \cdot 8} : \frac{1 + 57}{8}

m = \frac{- ( - 2 ) - 2 57}{2 \cdot 8} : \frac{1 - 57}{8}

The solutions to the quadratic equation are:

m = \frac{1 + 57}{8}, m = \frac{1 - 57}{8}

(x^{\frac{2}{3}})^{4}

\frac{- x + 2}{x - 4} \geq 0

2 - \frac{1}{5}

4 x^{2} - 4 x - 2

x^{2} - 3 x + 2 < 4 x - 8

What are the solutions to the equation 8m^2-2m-7=0 ?
The solutions to the equation 8m^2-2m-7=0 are m=(1+sqrt(57))/8 ,m=(1-sqrt(57))/8
Find the zeros of 8m^2-2m-7=0
The zeros of 8m^2-2m-7=0 are m=(1+sqrt(57))/8 ,m=(1-sqrt(57))/8