What are the solutions to the equation 5x^2+24x-5=0 ?

The solutions to the equation 5x^2+24x-5=0 are x= 1/5 ,x=-5

Find the zeros of 5x^2+24x-5=0

The zeros of 5x^2+24x-5=0 are x= 1/5 ,x=-5

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5 x^{2} + 24 x - 5 = 0

x = \frac{1}{5}, x = - 5

Decimal Notation

x = 0.2, x = - 5

Solution steps

5 x^{2} + 24 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

2 4^{2} - 4 \cdot 5 (- 5) = 26

x_{1, 2} = \frac{- 24 \pm 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 24 + 26}{2 \cdot 5}, x_{2} = \frac{- 24 - 26}{2 \cdot 5}

x = \frac{- 24 + 26}{2 \cdot 5} : \frac{1}{5}

x = \frac{- 24 - 26}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - 5

(x - 3)^{2} = - 5

1^{\frac{5}{2}}

y^{3} + 3 y^{2} - 4

y^{2} - 16 y + 55

\frac{1}{2} e^{\frac{- 3 πi}{4}}

What are the solutions to the equation 5x^2+24x-5=0 ?
The solutions to the equation 5x^2+24x-5=0 are x= 1/5 ,x=-5
Find the zeros of 5x^2+24x-5=0
The zeros of 5x^2+24x-5=0 are x= 1/5 ,x=-5