What are the solutions to the equation x^2+8x=2 ?

The solutions to the equation x^2+8x=2 are x=-4+3sqrt(2),x=-4-3sqrt(2)

Find the zeros of x^2+8x=2

The zeros of x^2+8x=2 are x=-4+3sqrt(2),x=-4-3sqrt(2)

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x^{2} + 8 x = 2

x = - 4 + 32, x = - 4 - 32

Decimal Notation

x = 0.24264 \dots, x = - 8.24264 \dots

Solution steps

x^{2} + 8 x = 2

Move

2

to the left side

x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 2) = 62

x_{1, 2} = \frac{- 8 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 6 2}{2 \cdot 1}

x = \frac{- 8 + 6 2}{2 \cdot 1} : - 4 + 32

x = \frac{- 8 - 6 2}{2 \cdot 1} : - 4 - 32

The solutions to the quadratic equation are:

x = - 4 + 32, x = - 4 - 32

6 \cdot 14

(2 x + 3)^{2} - 6 x - 9 = 0

6 = x \cdot 2

20 x^{2} - 28 x - 3

\frac{2}{1 - x} < \frac{1}{1 + x}

What are the solutions to the equation x^2+8x=2 ?
The solutions to the equation x^2+8x=2 are x=-4+3sqrt(2),x=-4-3sqrt(2)
Find the zeros of x^2+8x=2
The zeros of x^2+8x=2 are x=-4+3sqrt(2),x=-4-3sqrt(2)