What are the solutions to the equation 8x^2-2x-15=0 ?

The solutions to the equation 8x^2-2x-15=0 are x= 3/2 ,x=-5/4

Find the zeros of 8x^2-2x-15=0

The zeros of 8x^2-2x-15=0 are x= 3/2 ,x=-5/4

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8 x^{2} - 2 x - 15 = 0

x = \frac{3}{2}, x = - \frac{5}{4}

Decimal Notation

x = 1.5, x = - 1.25

Solution steps

8 x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 15) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 8}

x = \frac{- ( - 2 ) + 22}{2 \cdot 8} : \frac{3}{2}

x = \frac{- ( - 2 ) - 22}{2 \cdot 8} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{5}{4}

- 1 + \frac{4}{- 1}

4 y^{2} + 26 y + 30

x^{4} - x^{3} - 4 x^{2} + 4 x

4242

- 12 \geq 8 - \frac{4}{3} x

What are the solutions to the equation 8x^2-2x-15=0 ?
The solutions to the equation 8x^2-2x-15=0 are x= 3/2 ,x=-5/4
Find the zeros of 8x^2-2x-15=0
The zeros of 8x^2-2x-15=0 are x= 3/2 ,x=-5/4