What are the solutions to the equation 2n^2-7n+6=0 ?

The solutions to the equation 2n^2-7n+6=0 are n=2,n= 3/2

Find the zeros of 2n^2-7n+6=0

The zeros of 2n^2-7n+6=0 are n=2,n= 3/2

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2 n^{2} - 7 n + 6 = 0

n = 2, n = \frac{3}{2}

Decimal Notation

n = 2, n = 1.5

Solution steps

2 n^{2} - 7 n + 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 6 = 1

n_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 2}, n_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 2}

n = \frac{- ( - 7 ) + 1}{2 \cdot 2} : 2

n = \frac{- ( - 7 ) - 1}{2 \cdot 2} : \frac{3}{2}

The solutions to the quadratic equation are:

n = 2, n = \frac{3}{2}

ln (\frac{1}{e ^{5}})

\frac{x}{3} = 2

5 x^{3} + 7 x^{2} \geq 58 x + 24

13 x + 25 \leq - 1

4 x + 21 < 9

What are the solutions to the equation 2n^2-7n+6=0 ?
The solutions to the equation 2n^2-7n+6=0 are n=2,n= 3/2
Find the zeros of 2n^2-7n+6=0
The zeros of 2n^2-7n+6=0 are n=2,n= 3/2