What are the solutions to the equation -x^2-3x+2=6 ?

The solutions to the equation -x^2-3x+2=6 are x=-3/2-i(sqrt(7))/2 ,x=-3/2+i(sqrt(7))/2

Find the zeros of -x^2-3x+2=6

The zeros of -x^2-3x+2=6 are x=-3/2-i(sqrt(7))/2 ,x=-3/2+i(sqrt(7))/2

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- x^{2} - 3 x + 2 = 6

x = - \frac{3}{2} - i \frac{7}{2}, x = - \frac{3}{2} + i \frac{7}{2}

Solution steps

- x^{2} - 3 x + 2 = 6

Move

6

to the left side

- x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

Simplify

(- 3)^{2} - 4 (- 1) (- 4) : 7 i

x_{1, 2} = \frac{- ( - 3 ) \pm 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 7 i}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 7 i}{2 ( - 1 )} : - \frac{3}{2} - i \frac{7}{2}

x = \frac{- ( - 3 ) - 7 i}{2 ( - 1 )} : - \frac{3}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} - i \frac{7}{2}, x = - \frac{3}{2} + i \frac{7}{2}

9^{\frac{2}{3}} \cdot 3^{\frac{2}{3}}

6 x^{2} - 3 x - 1 = 0

- 6 x^{2} + 6 x

5 x^{4} + 10 x^{3} - 175 x^{2}

4 a + 4 b

What are the solutions to the equation -x^2-3x+2=6 ?
The solutions to the equation -x^2-3x+2=6 are x=-3/2-i(sqrt(7))/2 ,x=-3/2+i(sqrt(7))/2
Find the zeros of -x^2-3x+2=6
The zeros of -x^2-3x+2=6 are x=-3/2-i(sqrt(7))/2 ,x=-3/2+i(sqrt(7))/2