What are the solutions to the equation y^2-14y+49=-4 ?

The solutions to the equation y^2-14y+49=-4 are y=7+2i,y=7-2i

Find the zeros of y^2-14y+49=-4

The zeros of y^2-14y+49=-4 are y=7+2i,y=7-2i

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y^{2} - 14 y + 49 = - 4

y = 7 + 2 i, y = 7 - 2 i

Solution steps

y^{2} - 14 y + 49 = - 4

Move

4

to the left side

y^{2} - 14 y + 53 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 53}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 53 : 4 i

y_{1, 2} = \frac{- ( - 14 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 4 i}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 4 i}{2 \cdot 1}

y = \frac{- ( - 14 ) + 4 i}{2 \cdot 1} : 7 + 2 i

y = \frac{- ( - 14 ) - 4 i}{2 \cdot 1} : 7 - 2 i

The solutions to the quadratic equation are:

y = 7 + 2 i, y = 7 - 2 i

- 5 + 1

3 x^{2} + 24 = 18 x

11 - 6 (1 - x) \leq 6

16 - 4 x^{2} \geq 0

850

What are the solutions to the equation y^2-14y+49=-4 ?
The solutions to the equation y^2-14y+49=-4 are y=7+2i,y=7-2i
Find the zeros of y^2-14y+49=-4
The zeros of y^2-14y+49=-4 are y=7+2i,y=7-2i