What is (16r^3t^{-5})/(4r^{-1)t^2} ?

The solution to (16r^3t^{-5})/(4r^{-1)t^2} is (4r^4)/(t^7)

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simplify (16r^3t^{-5})/(4r^{-1)t^2}

simplify

\frac{16 r ^{3} t ^{- 5}}{4 r ^{- 1} t ^{2}}

\frac{4 r ^{4}}{t ^{7}}

Solution steps

\frac{16 r ^{3} t ^{- 5}}{4 r ^{- 1} t ^{2}}

Factor the number:

16 = 4 \cdot 4

= \frac{4 \cdot 4 r ^{3} t ^{- 5}}{4 r ^{- 1} t ^{2}}

Cancel the common factor:

4

= \frac{4 r ^{3} t ^{- 5}}{r ^{- 1} t ^{2}}

Simplify

\frac{r ^{3}}{r ^{- 1}} : r^{4}

= \frac{4 r ^{4} t ^{- 5}}{t ^{2}}

Simplify

\frac{t ^{- 5}}{t ^{2}} : \frac{1}{t ^{7}}

= \frac{4 r ^{4}}{t ^{7}}

6 x + 2 x^{2} = 0

\frac{30}{2 π}

1 - \frac{7}{8}

4 n^{4} - 16 n^{2} + 15

28 + 5 t = (5 + t)^{2}

What is (16r^3t^{-5})/(4r^{-1)t^2} ?
The solution to (16r^3t^{-5})/(4r^{-1)t^2} is (4r^4)/(t^7)