What are the solutions to the equation 2x^2=27+3x ?

The solutions to the equation 2x^2=27+3x are x= 9/2 ,x=-3

Find the zeros of 2x^2=27+3x

The zeros of 2x^2=27+3x are x= 9/2 ,x=-3

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2 x^{2} = 27 + 3 x

x = \frac{9}{2}, x = - 3

Decimal Notation

x = 4.5, x = - 3

Solution steps

2 x^{2} = 27 + 3 x

Move

3 x

to the left side

2 x^{2} - 3 x = 27

Move

27

to the left side

2 x^{2} - 3 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 27) = 15

x_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 2}

x = \frac{- ( - 3 ) + 15}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 3 ) - 15}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 3

- 11 - 8 k > 23 - (7 - 4 k)

576

2 x^{2} + 10 x y + 4 x^{3}

\frac{x}{- 2} = - 16

\frac{1.1}{0.07 - 0.2} (1 - (\frac{1.2}{1.07})^{4})

What are the solutions to the equation 2x^2=27+3x ?
The solutions to the equation 2x^2=27+3x are x= 9/2 ,x=-3
Find the zeros of 2x^2=27+3x
The zeros of 2x^2=27+3x are x= 9/2 ,x=-3