What are the solutions to the equation y^2+14y=-3 ?

The solutions to the equation y^2+14y=-3 are y=-7+sqrt(46),y=-7-sqrt(46)

Find the zeros of y^2+14y=-3

The zeros of y^2+14y=-3 are y=-7+sqrt(46),y=-7-sqrt(46)

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y^{2} + 14 y = - 3

y = - 7 + 46, y = - 7 - 46

Decimal Notation

y = - 0.21767 \dots, y = - 13.78232 \dots

Solution steps

y^{2} + 14 y = - 3

Move

3

to the left side

y^{2} + 14 y + 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 3 = 246

y_{1, 2} = \frac{- 14 \pm 2 46}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 14 + 2 46}{2 \cdot 1}, y_{2} = \frac{- 14 - 2 46}{2 \cdot 1}

y = \frac{- 14 + 2 46}{2 \cdot 1} : - 7 + 46

y = \frac{- 14 - 2 46}{2 \cdot 1} : - 7 - 46

The solutions to the quadratic equation are:

y = - 7 + 46, y = - 7 - 46

lo g_{e} (50) = x - 2

- 4 x + 4 < 16

5 t (6 t + 4)^{- \frac{1}{2}} + 6 (6 t + 4)^{\frac{1}{2}}

\frac{1}{4} x < (- \frac{3}{2} x + 6) + x

4 x^{2} - 8 x + 4 = 1

What are the solutions to the equation y^2+14y=-3 ?
The solutions to the equation y^2+14y=-3 are y=-7+sqrt(46),y=-7-sqrt(46)
Find the zeros of y^2+14y=-3
The zeros of y^2+14y=-3 are y=-7+sqrt(46),y=-7-sqrt(46)