What are the solutions to the equation (4x+3)^2=36 ?

The solutions to the equation (4x+3)^2=36 are x= 3/4 ,x=-9/4

Find the zeros of (4x+3)^2=36

The zeros of (4x+3)^2=36 are x= 3/4 ,x=-9/4

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(4 x + 3)^{2} = 36

x = \frac{3}{4}, x = - \frac{9}{4}

Decimal Notation

x = 0.75, x = - 2.25

Solution steps

(4 x + 3)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = 36 : x = \frac{3}{4}

Solve

4 x + 3 = - 36 : x = - \frac{9}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{9}{4}

(y - 3) (y + 2) = 0

- 4 x^{2} + 16 x + 84

2 (x + 6) = 17

v + 4 < 6

- 1 + \frac{3}{- 1}

What are the solutions to the equation (4x+3)^2=36 ?
The solutions to the equation (4x+3)^2=36 are x= 3/4 ,x=-9/4
Find the zeros of (4x+3)^2=36
The zeros of (4x+3)^2=36 are x= 3/4 ,x=-9/4