What are the solutions to the equation 8n^2+4=12n ?

The solutions to the equation 8n^2+4=12n are n=1,n= 1/2

Find the zeros of 8n^2+4=12n

The zeros of 8n^2+4=12n are n=1,n= 1/2

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8 n^{2} + 4 = 12 n

n = 1, n = \frac{1}{2}

Decimal Notation

n = 1, n = 0.5

Solution steps

8 n^{2} + 4 = 12 n

Move

12 n

to the left side

8 n^{2} + 4 - 12 n = 0

Write in the standard form

a x^{2} + b x + c = 0

8 n^{2} - 12 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 8 \cdot 4}{2 \cdot 8}

(- 12)^{2} - 4 \cdot 8 \cdot 4 = 4

n_{1, 2} = \frac{- ( - 12 ) \pm 4}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- ( - 12 ) + 4}{2 \cdot 8}, n_{2} = \frac{- ( - 12 ) - 4}{2 \cdot 8}

n = \frac{- ( - 12 ) + 4}{2 \cdot 8} : 1

n = \frac{- ( - 12 ) - 4}{2 \cdot 8} : \frac{1}{2}

The solutions to the quadratic equation are:

n = 1, n = \frac{1}{2}

x^{3} - 2 x - 56

\frac{1}{2 - 3} \cdot \frac{1}{2 + 3}

(0.08)^{2}

\frac{69.41 - 55}{8.1}

(x - 3)^{2} = 11

What are the solutions to the equation 8n^2+4=12n ?
The solutions to the equation 8n^2+4=12n are n=1,n= 1/2
Find the zeros of 8n^2+4=12n
The zeros of 8n^2+4=12n are n=1,n= 1/2