What are the solutions to the equation 5x^2-2x-6=0 ?

The solutions to the equation 5x^2-2x-6=0 are x=(1+sqrt(31))/5 ,x=(1-sqrt(31))/5

Find the zeros of 5x^2-2x-6=0

The zeros of 5x^2-2x-6=0 are x=(1+sqrt(31))/5 ,x=(1-sqrt(31))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 2 x - 6 = 0

x = \frac{1 + 31}{5}, x = \frac{1 - 31}{5}

Decimal Notation

x = 1.31355 \dots, x = - 0.91355 \dots

Solution steps

5 x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 6) = 231

x_{1, 2} = \frac{- ( - 2 ) \pm 2 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 31}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2 31}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2 31}{2 \cdot 5} : \frac{1 + 31}{5}

x = \frac{- ( - 2 ) - 2 31}{2 \cdot 5} : \frac{1 - 31}{5}

The solutions to the quadratic equation are:

x = \frac{1 + 31}{5}, x = \frac{1 - 31}{5}

4 - \frac{5}{2}

x + 5 = - 2 x - 4

\frac{x ^{2}}{16} + \frac{( x - 3 ) ^{2}}{4} = 1

(\frac{9}{49})^{\frac{1}{2}}

R (25) = - 6 x^{2} + 300 x + 30000

What are the solutions to the equation 5x^2-2x-6=0 ?
The solutions to the equation 5x^2-2x-6=0 are x=(1+sqrt(31))/5 ,x=(1-sqrt(31))/5
Find the zeros of 5x^2-2x-6=0
The zeros of 5x^2-2x-6=0 are x=(1+sqrt(31))/5 ,x=(1-sqrt(31))/5