What are the solutions to the equation y^2-8y+20=0 ?

The solutions to the equation y^2-8y+20=0 are y=4+2i,y=4-2i

Find the zeros of y^2-8y+20=0

The zeros of y^2-8y+20=0 are y=4+2i,y=4-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 8 y + 20 = 0

y = 4 + 2 i, y = 4 - 2 i

Solution steps

y^{2} - 8 y + 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 20 : 4 i

y_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 1}

y = \frac{- ( - 8 ) + 4 i}{2 \cdot 1} : 4 + 2 i

y = \frac{- ( - 8 ) - 4 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

y = 4 + 2 i, y = 4 - 2 i

(x + 3)^{2} = 9

x^{2} - 4 x = 17

4 x^{2} = 28

3 x + 4.5 = 4.5 x - 18

y^{2} + 4 y + 3 = 0

What are the solutions to the equation y^2-8y+20=0 ?
The solutions to the equation y^2-8y+20=0 are y=4+2i,y=4-2i
Find the zeros of y^2-8y+20=0
The zeros of y^2-8y+20=0 are y=4+2i,y=4-2i