What are the solutions to the equation 6x^2+14=19x ?

The solutions to the equation 6x^2+14=19x are x=2,x= 7/6

Find the zeros of 6x^2+14=19x

The zeros of 6x^2+14=19x are x=2,x= 7/6

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6 x^{2} + 14 = 19 x

x = 2, x = \frac{7}{6}

Decimal Notation

x = 2, x = 1.16666 \dots

Solution steps

6 x^{2} + 14 = 19 x

Move

19 x

to the left side

6 x^{2} + 14 - 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 19 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 6 \cdot 14}{2 \cdot 6}

(- 19)^{2} - 4 \cdot 6 \cdot 14 = 5

x_{1, 2} = \frac{- ( - 19 ) \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 5}{2 \cdot 6}, x_{2} = \frac{- ( - 19 ) - 5}{2 \cdot 6}

x = \frac{- ( - 19 ) + 5}{2 \cdot 6} : 2

x = \frac{- ( - 19 ) - 5}{2 \cdot 6} : \frac{7}{6}

The solutions to the quadratic equation are:

x = 2, x = \frac{7}{6}

\frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8}

6.25 x + 7.5 - 2.5 x = 3.75 x - 8.75

2 + \frac{1}{4}

∣ x - 177.2612 ∣ \leq 4.57

2 t^{2} - 32

What are the solutions to the equation 6x^2+14=19x ?
The solutions to the equation 6x^2+14=19x are x=2,x= 7/6
Find the zeros of 6x^2+14=19x
The zeros of 6x^2+14=19x are x=2,x= 7/6