What are the solutions to the equation 2x^2-x+6=-4x+8 ?

The solutions to the equation 2x^2-x+6=-4x+8 are x= 1/2 ,x=-2

Find the zeros of 2x^2-x+6=-4x+8

The zeros of 2x^2-x+6=-4x+8 are x= 1/2 ,x=-2

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2 x^{2} - x + 6 = - 4 x + 8

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

2 x^{2} - x + 6 = - 4 x + 8

Move

8

to the left side

2 x^{2} - x - 2 = - 4 x

Move

4 x

to the left side

2 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 2}, x_{2} = \frac{- 3 - 5}{2 \cdot 2}

x = \frac{- 3 + 5}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 3 - 5}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

- 48 = 6 (x - 3)

\frac{1}{3} (48 n + 9) + 1 = \frac{1}{5} (30 + 30 n)

∣ - 5 ∣ + 9

x^{2} + 10 x + 25 \geq 0

7 x^{5} y^{7} + 14 x^{6} y^{6}

What are the solutions to the equation 2x^2-x+6=-4x+8 ?
The solutions to the equation 2x^2-x+6=-4x+8 are x= 1/2 ,x=-2
Find the zeros of 2x^2-x+6=-4x+8
The zeros of 2x^2-x+6=-4x+8 are x= 1/2 ,x=-2