What is 9-|x+3|>= 5 ?

The solution to 9-|x+3|>= 5 is -7<= x<= 1

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9-|x+3|>= 5

9 - ∣ x + 3 ∣ \geq 5

- 7 \leq x \leq 1

Interval Notation

[- 7, 1]

Solution steps

9 - ∣ x + 3 ∣ \geq 5

Move

9

to the right side

- ∣ x + 3 ∣ \geq - 4

Multiply both sides by

- 1

∣ x + 3 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x + 3 \leq 4

x + 3 \geq - 4 and x + 3 \leq 4

x \geq - 7 and x \leq 1

Merge Overlapping Intervals

- 7 \leq x \leq 1

(2 x^{3})^{4}

927

lo g_{5} (32)

lo g_{a} (M^{r})

- \frac{2}{\frac{π}{2}}