What are the solutions to the equation -5x^2+80x-365=0 ?

The solutions to the equation -5x^2+80x-365=0 are x=8-3i,x=8+3i

Find the zeros of -5x^2+80x-365=0

The zeros of -5x^2+80x-365=0 are x=8-3i,x=8+3i

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- 5 x^{2} + 80 x - 365 = 0

x = 8 - 3 i, x = 8 + 3 i

Solution steps

- 5 x^{2} + 80 x - 365 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 5 ) ( - 365 )}{2 ( - 5 )}

Simplify

8 0^{2} - 4 (- 5) (- 365) : 30 i

x_{1, 2} = \frac{- 80 \pm 30 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 80 + 30 i}{2 ( - 5 )}, x_{2} = \frac{- 80 - 30 i}{2 ( - 5 )}

x = \frac{- 80 + 30 i}{2 ( - 5 )} : 8 - 3 i

x = \frac{- 80 - 30 i}{2 ( - 5 )} : 8 + 3 i

The solutions to the quadratic equation are:

x = 8 - 3 i, x = 8 + 3 i

∣ 2 x + 7 ∣ < 8

12 n + 20 n^{2}

8 x^{2} + 2 x \geq 1

(80 i) - (80 + 10 i)

7 ∣ x - 2 ∣ + 7 = - 2 ∣ x - 2 ∣ + 2

What are the solutions to the equation -5x^2+80x-365=0 ?
The solutions to the equation -5x^2+80x-365=0 are x=8-3i,x=8+3i
Find the zeros of -5x^2+80x-365=0
The zeros of -5x^2+80x-365=0 are x=8-3i,x=8+3i