What are the solutions to the equation 9x^2+x+1=0 ?

The solutions to the equation 9x^2+x+1=0 are x=-1/18+i(sqrt(35))/(18),x=-1/18-i(sqrt(35))/(18)

Find the zeros of 9x^2+x+1=0

The zeros of 9x^2+x+1=0 are x=-1/18+i(sqrt(35))/(18),x=-1/18-i(sqrt(35))/(18)

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9 x^{2} + x + 1 = 0

x = - \frac{1}{18} + i \frac{35}{18}, x = - \frac{1}{18} - i \frac{35}{18}

Solution steps

9 x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

Simplify

1^{2} - 4 \cdot 9 \cdot 1 : 35 i

x_{1, 2} = \frac{- 1 \pm 35 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 1 + 35 i}{2 \cdot 9}, x_{2} = \frac{- 1 - 35 i}{2 \cdot 9}

x = \frac{- 1 + 35 i}{2 \cdot 9} : - \frac{1}{18} + i \frac{35}{18}

x = \frac{- 1 - 35 i}{2 \cdot 9} : - \frac{1}{18} - i \frac{35}{18}

The solutions to the quadratic equation are:

x = - \frac{1}{18} + i \frac{35}{18}, x = - \frac{1}{18} - i \frac{35}{18}

x - \frac{x - y}{x + y}

\frac{14}{3}

- 2 \leq 3 x + 2 \leq 3

x^{\frac{5}{2}} - x^{\frac{1}{2}}

8 1^{- \frac{1}{2}}

What are the solutions to the equation 9x^2+x+1=0 ?
The solutions to the equation 9x^2+x+1=0 are x=-1/18+i(sqrt(35))/(18),x=-1/18-i(sqrt(35))/(18)
Find the zeros of 9x^2+x+1=0
The zeros of 9x^2+x+1=0 are x=-1/18+i(sqrt(35))/(18),x=-1/18-i(sqrt(35))/(18)