What are the solutions to the equation 2x^2-24x+216=0 ?

The solutions to the equation 2x^2-24x+216=0 are x=6+6sqrt(2)i,x=6-6sqrt(2)i

Find the zeros of 2x^2-24x+216=0

The zeros of 2x^2-24x+216=0 are x=6+6sqrt(2)i,x=6-6sqrt(2)i

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2 x^{2} - 24 x + 216 = 0

x = 6 + 62 i, x = 6 - 62 i

Solution steps

2 x^{2} - 24 x + 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 216}{2 \cdot 2}

Simplify

(- 24)^{2} - 4 \cdot 2 \cdot 216 : 242 i

x_{1, 2} = \frac{- ( - 24 ) \pm 24 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 24 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 24 ) - 24 2 i}{2 \cdot 2}

x = \frac{- ( - 24 ) + 24 2 i}{2 \cdot 2} : 6 + 62 i

x = \frac{- ( - 24 ) - 24 2 i}{2 \cdot 2} : 6 - 62 i

The solutions to the quadratic equation are:

x = 6 + 62 i, x = 6 - 62 i

6 n^{2} + n - 2

- \frac{3}{- 4}

b^{8} c^{11} + b^{5} c^{6}

- 2 ∣ x - 2 ∣ + 8 = - 4

5 a c - 5 b c - a + b

What are the solutions to the equation 2x^2-24x+216=0 ?
The solutions to the equation 2x^2-24x+216=0 are x=6+6sqrt(2)i,x=6-6sqrt(2)i
Find the zeros of 2x^2-24x+216=0
The zeros of 2x^2-24x+216=0 are x=6+6sqrt(2)i,x=6-6sqrt(2)i