What are the solutions to the equation -3(x+2)^2=-18 ?

The solutions to the equation -3(x+2)^2=-18 are x=sqrt(6)-2,x=-sqrt(6)-2

Find the zeros of -3(x+2)^2=-18

The zeros of -3(x+2)^2=-18 are x=sqrt(6)-2,x=-sqrt(6)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 (x + 2)^{2} = - 18

x = 6 - 2, x = - 6 - 2

Decimal Notation

x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

- 3 (x + 2)^{2} = - 18

Divide both sides by

- 3

(x + 2)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 6 : x = 6 - 2

Solve

x + 2 = - 6 : x = - 6 - 2

The solutions to the quadratic equation are:

x = 6 - 2, x = - 6 - 2

0.8 \cdot 5

(x + 5)^{2} = 49

\frac{3}{3} + \frac{3}{3}

lo g_{\frac{1}{64}} (16) = \frac{4}{7} x - \frac{11}{2}

\frac{x - 4}{2 x + 9} \geq 1

What are the solutions to the equation -3(x+2)^2=-18 ?
The solutions to the equation -3(x+2)^2=-18 are x=sqrt(6)-2,x=-sqrt(6)-2
Find the zeros of -3(x+2)^2=-18
The zeros of -3(x+2)^2=-18 are x=sqrt(6)-2,x=-sqrt(6)-2