What is factor z^2+4z^6 ?

The solution to factor z^2+4z^6 is z^2(2z^2+2z+1)(2z^2-2z+1)

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factor z^2+4z^6

factor

z^{2} + 4 z^{6}

z^{2} (2 z^{2} + 2 z + 1) (2 z^{2} - 2 z + 1)

Solution steps

z^{2} + 4 z^{6}

Write in the standard form

= 4 z^{6} + z^{2}

Factor out common term

z^{2} : z^{2} (4 z^{4} + 1)

= z^{2} (4 z^{4} + 1)

Factor

4 z^{4} + 1 : (2 z^{2} + 2 z + 1) (2 z^{2} - 2 z + 1)

= z^{2} (2 z^{2} + 2 z + 1) (2 z^{2} - 2 z + 1)

6 x^{2} - 36 x + 48

28 x^{3} - 7 x

x^{2} + 2 = 2

\frac{1}{25} - 25 z^{2}

What is factor z^2+4z^6 ?
The solution to factor z^2+4z^6 is z^2(2z^2+2z+1)(2z^2-2z+1)