What is factor 8t^4-32t^3+t-4 ?

The solution to factor 8t^4-32t^3+t-4 is (t-4)(2t+1)(4t^2-2t+1)

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factor 8t^4-32t^3+t-4

factor

8 t^{4} - 32 t^{3} + t - 4

(t - 4) (2 t + 1) (4 t^{2} - 2 t + 1)

Solution steps

8 t^{4} - 32 t^{3} + t - 4

= (8 t^{4} - 32 t^{3}) + (t - 4)

Factor out

8 t^{3}

from

8 t^{4} - 32 t^{3} : 8 t^{3} (t - 4)

= 8 t^{3} (t - 4) + (t - 4)

Factor out common term

(t - 4) : (t - 4) (8 t^{3} + 1)

= (t - 4) (8 t^{3} + 1)

Factor

8 t^{3} + 1 : (2 t + 1) (2^{2} t^{2} - 2 t + 1)

= (t - 4) (2 t + 1) (2^{2} t^{2} - 2 t + 1)

2^{2} = 4

= (t - 4) (2 t + 1) (4 t^{2} - 2 t + 1)

3 m^{2} + 11 mn + 6 n^{2}

\frac{5}{2} \cdot \frac{1}{4}

9 x^{2} - 42 x + 49

x^{2} + 5 = 4

- \frac{13}{3} \cdot (- \frac{7}{3} + \frac{10}{3})

What is factor 8t^4-32t^3+t-4 ?
The solution to factor 8t^4-32t^3+t-4 is (t-4)(2t+1)(4t^2-2t+1)