What are the solutions to the equation x^2-16x+54=0 ?

The solutions to the equation x^2-16x+54=0 are x=8+sqrt(10),x=8-sqrt(10)

Find the zeros of x^2-16x+54=0

The zeros of x^2-16x+54=0 are x=8+sqrt(10),x=8-sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 16 x + 54 = 0

x = 8 + 10, x = 8 - 10

Decimal Notation

x = 11.16227 \dots, x = 4.83772 \dots

Solution steps

x^{2} - 16 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 54 = 210

x_{1, 2} = \frac{- ( - 16 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 10}{2 \cdot 1} : 8 + 10

x = \frac{- ( - 16 ) - 2 10}{2 \cdot 1} : 8 - 10

The solutions to the quadratic equation are:

x = 8 + 10, x = 8 - 10

8 - x^{2} \leq 10

∣ 2 x + 4 ∣ \geq 10

- 4 + \frac{x}{5} = 12

7 x + y - x y - 7 - z^{2} + x z^{2}

\frac{a - 7}{3} = \frac{a + 5}{2} - \frac{7 a - 1}{6}

What are the solutions to the equation x^2-16x+54=0 ?
The solutions to the equation x^2-16x+54=0 are x=8+sqrt(10),x=8-sqrt(10)
Find the zeros of x^2-16x+54=0
The zeros of x^2-16x+54=0 are x=8+sqrt(10),x=8-sqrt(10)