What is (2/5 m^2n+1/3 mn)(3/2 m^2n+2mn^{-3}) ?

The solution to (2/5 m^2n+1/3 mn)(3/2 m^2n+2mn^{-3}) is (2/5 m^2n+1/3 mn)((3m^2n)/2+(2m)/(n^3))

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simplify (2/5 m^2n+1/3 mn)(3/2 m^2n+2mn^{-3})

simplify

(\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 m n^{- 3})

(\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3 m ^{2} n}{2} + \frac{2 m}{n ^{3}})

Solution steps

(\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 m n^{- 3})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

n^{- 3} = \frac{1}{n ^{3}}

= (\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 m \frac{1}{n ^{3}})

Simplify

\frac{3}{2} m^{2} n + 2 m \frac{1}{n ^{3}} : \frac{3 m ^{2} n}{2} + \frac{2 m}{n ^{3}}

= (\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3 m ^{2} n}{2} + \frac{2 m}{n ^{3}})

4 x + 2 - 15 < - 1

x^{2} + 7 x - 45 = 7

5^{2} + 9^{2} = c^{2}

5 x^{3} + 5 x^{2} - 10 x

\frac{40 x}{10} = 28

What is (2/5 m^2n+1/3 mn)(3/2 m^2n+2mn^{-3}) ?
The solution to (2/5 m^2n+1/3 mn)(3/2 m^2n+2mn^{-3}) is (2/5 m^2n+1/3 mn)((3m^2n)/2+(2m)/(n^3))