What is factor 49a^2-28a+4 ?

The solution to factor 49a^2-28a+4 is (7a-2)^2

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factor 49a^2-28a+4

factor

49 a^{2} - 28 a + 4

(7 a - 2)^{2}

Solution steps

49 a^{2} - 28 a + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 a^{2} = (7 a)^{2}

4 = 2^{2}

- 28 a = - 2 \cdot 7 a \cdot 2

= (7 a)^{2} - 2 \cdot 7 a \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(7 a)^{2} - 2 \cdot 7 a \cdot 2 + 2^{2} = (7 a - 2)^{2}

= (7 a - 2)^{2}

x^{2} - 3 x - 2 = 0

5 x^{2} + 3 x + 1 = 0

\frac{\frac{- 1}{2}}{\frac{3}{2}}

10 x + 9 \leq 5 + 9

a^{2} + 17 a + 60