|x-1|<= x

Solution

∣ x - 1 ∣ \leq x

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Decimal Notation

x \geq 0.5

Solution steps

∣ x - 1 ∣ \leq x

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

\frac{1}{2} \leq x < 1 or x \geq 1

Merge Overlapping Intervals

x \geq \frac{1}{2}

∣ z ∣ = - 4

m^{2} - 81 = 0

\frac{9}{6}

- 2 (x + 3) + 4 x - 4 = - 14

x^{2} - 5 x - 14 > 0