What are the solutions to the equation 3x^2-4x-4=0 ?

The solutions to the equation 3x^2-4x-4=0 are x=2,x=-2/3

Find the zeros of 3x^2-4x-4=0

The zeros of 3x^2-4x-4=0 are x=2,x=-2/3

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3 x^{2} - 4 x - 4 = 0

x = 2, x = - \frac{2}{3}

Decimal Notation

x = 2, x = - 0.66666 \dots

Solution steps

3 x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 4) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 3}

x = \frac{- ( - 4 ) + 8}{2 \cdot 3} : 2

x = \frac{- ( - 4 ) - 8}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{2}{3}

(x y + \frac{z}{2})^{2}

e^{l n (3)}

2 x - x = 3 x - 12

\frac{12 !}{4 ! 8 !}

25 (25) + 12 (12) + 4 \leq 130

What are the solutions to the equation 3x^2-4x-4=0 ?
The solutions to the equation 3x^2-4x-4=0 are x=2,x=-2/3
Find the zeros of 3x^2-4x-4=0
The zeros of 3x^2-4x-4=0 are x=2,x=-2/3