What are the solutions to the equation x^2-16x+91=0 ?

The solutions to the equation x^2-16x+91=0 are x=8+3sqrt(3)i,x=8-3sqrt(3)i

Find the zeros of x^2-16x+91=0

The zeros of x^2-16x+91=0 are x=8+3sqrt(3)i,x=8-3sqrt(3)i

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x^{2} - 16 x + 91 = 0

x = 8 + 33 i, x = 8 - 33 i

Solution steps

x^{2} - 16 x + 91 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 91}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 91 : 63 i

x_{1, 2} = \frac{- ( - 16 ) \pm 6 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 6 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 6 3 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 6 3 i}{2 \cdot 1} : 8 + 33 i

x = \frac{- ( - 16 ) - 6 3 i}{2 \cdot 1} : 8 - 33 i

The solutions to the quadratic equation are:

x = 8 + 33 i, x = 8 - 33 i

\frac{- 6}{9}

x^{2} + 5 x y - 50 y^{2}

5 x^{4} - 405

4 \cdot 24

\frac{6}{5} x = 12

What are the solutions to the equation x^2-16x+91=0 ?
The solutions to the equation x^2-16x+91=0 are x=8+3sqrt(3)i,x=8-3sqrt(3)i
Find the zeros of x^2-16x+91=0
The zeros of x^2-16x+91=0 are x=8+3sqrt(3)i,x=8-3sqrt(3)i