What are the solutions to the equation -3(x-1)(x+1/2)=0 ?

The solutions to the equation -3(x-1)(x+1/2)=0 are x=1,x=-1/2

Find the zeros of -3(x-1)(x+1/2)=0

The zeros of -3(x-1)(x+1/2)=0 are x=1,x=-1/2

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- 3 (x - 1) (x + \frac{1}{2}) = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

- 3 (x - 1) (x + \frac{1}{2}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + \frac{1}{2} = 0

Solve

x - 1 = 0 : x = 1

Solve

x + \frac{1}{2} = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

2 - \frac{1}{1 - \frac{1}{1 - \frac{1}{2}}}

441 = 144 + x^{2}

6 n^{2} - 18 n - 18 = 6

x^{2} - 5 \leq 0

x^{4} - 4 x^{3} - x^{2} + 14 x + 10

What are the solutions to the equation -3(x-1)(x+1/2)=0 ?
The solutions to the equation -3(x-1)(x+1/2)=0 are x=1,x=-1/2
Find the zeros of -3(x-1)(x+1/2)=0
The zeros of -3(x-1)(x+1/2)=0 are x=1,x=-1/2