What are the solutions to the equation z^2+z-1=0 ?

The solutions to the equation z^2+z-1=0 are z=(-1+sqrt(5))/2 ,z=(-1-sqrt(5))/2

Find the zeros of z^2+z-1=0

The zeros of z^2+z-1=0 are z=(-1+sqrt(5))/2 ,z=(-1-sqrt(5))/2

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z^{2} + z - 1 = 0

z = \frac{- 1 + 5}{2}, z = \frac{- 1 - 5}{2}

Decimal Notation

z = 0.61803 \dots, z = - 1.61803 \dots

Solution steps

z^{2} + z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 1) = 5

z_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 5}{2 \cdot 1}, z_{2} = \frac{- 1 - 5}{2 \cdot 1}

z = \frac{- 1 + 5}{2 \cdot 1} : \frac{- 1 + 5}{2}

z = \frac{- 1 - 5}{2 \cdot 1} : \frac{- 1 - 5}{2}

The solutions to the quadratic equation are:

z = \frac{- 1 + 5}{2}, z = \frac{- 1 - 5}{2}

\frac{x ^{2} - 1}{x ^{2} + 5 x + 4} \leq 0

∣ x + 3 ∣ > 0

\frac{6 x - 6}{8} = - 5 x + 28

1 + \frac{0.05}{12}

7 (x + 4) = 2 x + 6

What are the solutions to the equation z^2+z-1=0 ?
The solutions to the equation z^2+z-1=0 are z=(-1+sqrt(5))/2 ,z=(-1-sqrt(5))/2
Find the zeros of z^2+z-1=0
The zeros of z^2+z-1=0 are z=(-1+sqrt(5))/2 ,z=(-1-sqrt(5))/2