What are the solutions to the equation (x+5)(x-5)=-7 ?

The solutions to the equation (x+5)(x-5)=-7 are x=3sqrt(2),x=-3sqrt(2)

Find the zeros of (x+5)(x-5)=-7

The zeros of (x+5)(x-5)=-7 are x=3sqrt(2),x=-3sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 5) (x - 5) = - 7

x = 32, x = - 32

Decimal Notation

x = 4.24264 \dots, x = - 4.24264 \dots

Solution steps

(x + 5) (x - 5) = - 7

Expand

(x + 5) (x - 5) : x^{2} - 25

x^{2} - 25 = - 7

Move

7

to the left side

x^{2} - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 18) = 62

x_{1, 2} = \frac{- 0 \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 6 2}{2 \cdot 1}, x_{2} = \frac{- 0 - 6 2}{2 \cdot 1}

x = \frac{- 0 + 6 2}{2 \cdot 1} : 32

x = \frac{- 0 - 6 2}{2 \cdot 1} : - 32

The solutions to the quadratic equation are:

x = 32, x = - 32

3 ∣ 2 x - 5 ∣ = 9

73 \cdot 2

(x - 2) (3 x + 5) - (x - 2) (5 x - 4)

∣ x + 7 ∣ < 1

8 x + 24

What are the solutions to the equation (x+5)(x-5)=-7 ?
The solutions to the equation (x+5)(x-5)=-7 are x=3sqrt(2),x=-3sqrt(2)
Find the zeros of (x+5)(x-5)=-7
The zeros of (x+5)(x-5)=-7 are x=3sqrt(2),x=-3sqrt(2)