What are the solutions to the equation (j-7)^2=39 ?

The solutions to the equation (j-7)^2=39 are j=sqrt(39)+7,j=-sqrt(39)+7

Find the zeros of (j-7)^2=39

The zeros of (j-7)^2=39 are j=sqrt(39)+7,j=-sqrt(39)+7

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(j - 7)^{2} = 39

j = 39 + 7, j = - 39 + 7

Decimal Notation

j = 13.24499 \dots, j = 0.75500 \dots

Solution steps

(j - 7)^{2} = 39

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

j - 7 = 39 : j = 39 + 7

Solve

j - 7 = - 39 : j = - 39 + 7

The solutions to the quadratic equation are:

j = 39 + 7, j = - 39 + 7

x^{3} + 2 x^{2} - 11 x - 12 \geq 0

5 m - (3 m + 11) > 6 (m + 5) - (- 3 m)

(\frac{1}{2})^{10}

3 (- 2 x + 4) - 4 x - 2 = 20

10000 \cdot \frac{907185}{2000}

What are the solutions to the equation (j-7)^2=39 ?
The solutions to the equation (j-7)^2=39 are j=sqrt(39)+7,j=-sqrt(39)+7
Find the zeros of (j-7)^2=39
The zeros of (j-7)^2=39 are j=sqrt(39)+7,j=-sqrt(39)+7