What are the solutions to the equation -4x^2+8x=11 ?

The solutions to the equation -4x^2+8x=11 are x=1-i(sqrt(7))/2 ,x=1+i(sqrt(7))/2

Find the zeros of -4x^2+8x=11

The zeros of -4x^2+8x=11 are x=1-i(sqrt(7))/2 ,x=1+i(sqrt(7))/2

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- 4 x^{2} + 8 x = 11

x = 1 - i \frac{7}{2}, x = 1 + i \frac{7}{2}

Solution steps

- 4 x^{2} + 8 x = 11

Move

11

to the left side

- 4 x^{2} + 8 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) ( - 11 )}{2 ( - 4 )}

Simplify

8^{2} - 4 (- 4) (- 11) : 47 i

x_{1, 2} = \frac{- 8 \pm 4 7 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 7 i}{2 ( - 4 )}, x_{2} = \frac{- 8 - 4 7 i}{2 ( - 4 )}

x = \frac{- 8 + 4 7 i}{2 ( - 4 )} : 1 - i \frac{7}{2}

x = \frac{- 8 - 4 7 i}{2 ( - 4 )} : 1 + i \frac{7}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{7}{2}, x = 1 + i \frac{7}{2}

(- 243)^{\frac{1}{5}}

3 w^{2} - 4 w + 5 = 0

625 x - 100 x^{2} + 4 x^{3} > 1000

2 a^{2} b - 4 a b^{2}

\frac{1}{3} (2 x + 8) + \frac{4 x - 8}{6} = - x + \frac{7}{2}

What are the solutions to the equation -4x^2+8x=11 ?
The solutions to the equation -4x^2+8x=11 are x=1-i(sqrt(7))/2 ,x=1+i(sqrt(7))/2
Find the zeros of -4x^2+8x=11
The zeros of -4x^2+8x=11 are x=1-i(sqrt(7))/2 ,x=1+i(sqrt(7))/2