What is ((3x^{3/2}y^3)/(x^2y^{-1/2)})^{-2} ?

The solution to ((3x^{3/2}y^3)/(x^2y^{-1/2)})^{-2} is x/(9y^7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((3x^{3/2}y^3)/(x^2y^{-1/2)})^{-2}

simplify

(\frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}})^{- 2}

\frac{x}{9 y ^{7}}

Solution steps

(\frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}})^{- 2} = \frac{1}{( \frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}} ) ^{2}}

= \frac{1}{( \frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}} ) ^{2}}

Simplify

(\frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}})^{2} : \frac{9 y ^{7}}{x}

= \frac{1}{\frac{9 y ^{7}}{x}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x}{9 y ^{7}}

\frac{11 !}{3 ! 8 !}

\frac{x}{4} + 2 = 5

\frac{1}{x + 1} > \frac{x - 1}{x ^{2} + 1}

6 y - 30 < - 15 + 3 y

3 x + 2 = 2 x + 3

What is ((3x^{3/2}y^3)/(x^2y^{-1/2)})^{-2} ?
The solution to ((3x^{3/2}y^3)/(x^2y^{-1/2)})^{-2} is x/(9y^7)