What are the solutions to the equation 8y^2+4y-24=0 ?

The solutions to the equation 8y^2+4y-24=0 are y= 3/2 ,y=-2

Find the zeros of 8y^2+4y-24=0

The zeros of 8y^2+4y-24=0 are y= 3/2 ,y=-2

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8 y^{2} + 4 y - 24 = 0

y = \frac{3}{2}, y = - 2

Decimal Notation

y = 1.5, y = - 2

Solution steps

8 y^{2} + 4 y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 8 ( - 24 )}{2 \cdot 8}

4^{2} - 4 \cdot 8 (- 24) = 28

y_{1, 2} = \frac{- 4 \pm 28}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- 4 + 28}{2 \cdot 8}, y_{2} = \frac{- 4 - 28}{2 \cdot 8}

y = \frac{- 4 + 28}{2 \cdot 8} : \frac{3}{2}

y = \frac{- 4 - 28}{2 \cdot 8} : - 2

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - 2

x + 3 = 11

- x^{2} + 4 x + 4 = 0

45 + 20 - 5

x^{- 2}

2 x^{2} + 5 x - 2 = 0

What are the solutions to the equation 8y^2+4y-24=0 ?
The solutions to the equation 8y^2+4y-24=0 are y= 3/2 ,y=-2
Find the zeros of 8y^2+4y-24=0
The zeros of 8y^2+4y-24=0 are y= 3/2 ,y=-2