What are the solutions to the equation 3x^2+6x-9=0 ?

The solutions to the equation 3x^2+6x-9=0 are x=1,x=-3

Find the zeros of 3x^2+6x-9=0

The zeros of 3x^2+6x-9=0 are x=1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 6 x - 9 = 0

x = 1, x = - 3

Solution steps

3 x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 9) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 3}, x_{2} = \frac{- 6 - 12}{2 \cdot 3}

x = \frac{- 6 + 12}{2 \cdot 3} : 1

x = \frac{- 6 - 12}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

(e^{2 x})^{2}

c^{2} + 93 c + 92

975

\frac{x ^{2} + x - 12}{x ^{2} - 4 x + 4} > 0

lo g_{2} (\frac{1}{50})

What are the solutions to the equation 3x^2+6x-9=0 ?
The solutions to the equation 3x^2+6x-9=0 are x=1,x=-3
Find the zeros of 3x^2+6x-9=0
The zeros of 3x^2+6x-9=0 are x=1,x=-3