What are the solutions to the equation (z+9)^2=-49 ?

The solutions to the equation (z+9)^2=-49 are z=7i-9,z=-7i-9

Find the zeros of (z+9)^2=-49

The zeros of (z+9)^2=-49 are z=7i-9,z=-7i-9

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(z + 9)^{2} = - 49

z = 7 i - 9, z = - 7 i - 9

Solution steps

(z + 9)^{2} = - 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 9 = - 49 : z = 7 i - 9

Solve

z + 9 = - - 49 : z = - 7 i - 9

The solutions to the quadratic equation are:

z = 7 i - 9, z = - 7 i - 9

2 x (x - 1) = 4

- 5 \frac{x}{3} - 4 + 11 = - 14

16 x^{2} (4 x - 3) - 9 (4 x - 3)

8^{3} = - 1

1 + \frac{7 x}{9} - \frac{1}{7} (x + 9) \geq x

What are the solutions to the equation (z+9)^2=-49 ?
The solutions to the equation (z+9)^2=-49 are z=7i-9,z=-7i-9
Find the zeros of (z+9)^2=-49
The zeros of (z+9)^2=-49 are z=7i-9,z=-7i-9