What are the solutions to the equation p^2+2p-24=0 ?

The solutions to the equation p^2+2p-24=0 are p=4,p=-6

Find the zeros of p^2+2p-24=0

The zeros of p^2+2p-24=0 are p=4,p=-6

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p^{2} + 2 p - 24 = 0

p = 4, p = - 6

Solution steps

p^{2} + 2 p - 24 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

p_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 10}{2 \cdot 1}, p_{2} = \frac{- 2 - 10}{2 \cdot 1}

p = \frac{- 2 + 10}{2 \cdot 1} : 4

p = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

p = 4, p = - 6

\frac{x ^{\frac{1}{4}}}{x ^{- \frac{3}{4}}}

\frac{8}{a} - \frac{6}{a} + \frac{7}{a}

8 - (- 5)

(- x^{5})^{2}

9 x^{3} - 81 x

What are the solutions to the equation p^2+2p-24=0 ?
The solutions to the equation p^2+2p-24=0 are p=4,p=-6
Find the zeros of p^2+2p-24=0
The zeros of p^2+2p-24=0 are p=4,p=-6