What are the solutions to the equation x^2-8x+6=0 ?

The solutions to the equation x^2-8x+6=0 are x=4+sqrt(10),x=4-sqrt(10)

Find the zeros of x^2-8x+6=0

The zeros of x^2-8x+6=0 are x=4+sqrt(10),x=4-sqrt(10)

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x^{2} - 8 x + 6 = 0

x = 4 + 10, x = 4 - 10

Decimal Notation

x = 7.16227 \dots, x = 0.83772 \dots

Solution steps

x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 6 = 210

x_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 10}{2 \cdot 1} : 4 + 10

x = \frac{- ( - 8 ) - 2 10}{2 \cdot 1} : 4 - 10

The solutions to the quadratic equation are:

x = 4 + 10, x = 4 - 10

3 d + 1 > 7

7 x \leq - 28 or x - 8 > 0

\frac{3 + i}{3 - i}

2 (x - 3) - 17 = 13 - 3 (x + 2)

\frac{3}{4} - 3 r > - 48

What are the solutions to the equation x^2-8x+6=0 ?
The solutions to the equation x^2-8x+6=0 are x=4+sqrt(10),x=4-sqrt(10)
Find the zeros of x^2-8x+6=0
The zeros of x^2-8x+6=0 are x=4+sqrt(10),x=4-sqrt(10)