What is factor 1-m^2n^4 ?

The solution to factor 1-m^2n^4 is (1+mn^2)(1-mn^2)

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factor 1-m^2n^4

factor

1 - m^{2} n^{4}

(1 + m n^{2}) (1 - m n^{2})

Solution steps

1 - m^{2} n^{4}

1 = 1^{2}

m^{2} n^{4} = (m n^{2})^{2}

= 1^{2} - (m n^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

1^{2} - (m n^{2})^{2} = (1 + m n^{2}) (1 - m n^{2})

= (1 + m n^{2}) (1 - m n^{2})

\frac{x}{17} = 5

\frac{9 !}{6 !}

16 g h - 10 g^{2} h

(t^{2})^{3}

x (x + 1) - \frac{1}{2} = \frac{x - 4}{6}