What are the solutions to the equation x^2-4x-91=0 ?

The solutions to the equation x^2-4x-91=0 are x=2+sqrt(95),x=2-sqrt(95)

Find the zeros of x^2-4x-91=0

The zeros of x^2-4x-91=0 are x=2+sqrt(95),x=2-sqrt(95)

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x^{2} - 4 x - 91 = 0

x = 2 + 95, x = 2 - 95

Decimal

x = 11.74679 \dots, x = - 7.74679 \dots

Solution steps

x^{2} - 4 x - 91 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 91 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 91) = 295

x_{1, 2} = \frac{- ( - 4 ) \pm 2 95}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 95}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 95}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 95}{2 \cdot 1} : 2 + 95

x = \frac{- ( - 4 ) - 2 95}{2 \cdot 1} : 2 - 95

The solutions to the quadratic equation are:

x = 2 + 95, x = 2 - 95

x^{2} + 1 = - 3 x + 11

7 x^{2} - 48 x - 7

\frac{\frac{1}{3}}{2}

\frac{x ^{2} + 14 x + 49}{x ^{2} - x - 30} \leq 0

(x + 6)^{2} = 3

What are the solutions to the equation x^2-4x-91=0 ?
The solutions to the equation x^2-4x-91=0 are x=2+sqrt(95),x=2-sqrt(95)
Find the zeros of x^2-4x-91=0
The zeros of x^2-4x-91=0 are x=2+sqrt(95),x=2-sqrt(95)