What is the answer to 2x+3(x-3)=6[2x-3(x-5)] ?

The answer to 2x+3(x-3)=6[2x-3(x-5)] is x=9

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2x+3(x-3)=6[2x-3(x-5)]

2 x + 3 (x - 3) = 6 [2 x - 3 (x - 5)]

x = 9

Solution steps

2 x + 3 (x - 3) = 6 [2 x - 3 (x - 5)]

Expand

3 (x - 3) : 3 x - 9

2 x + 3 x - 9 = 6 [2 x - 3 (x - 5)]

Add similar elements:

2 x + 3 x = 5 x

5 x - 9 = 6 [2 x - 3 (x - 5)]

Expand

6 (2 x - 3 (x - 5)) : - 6 x + 90

5 x - 9 = - 6 x + 90

Move

9

to the right side

5 x = - 6 x + 99

Move

6 x

to the left side

11 x = 99

Divide both sides by

11

x = 9

2 (- 8 + x) = - 10

x^{4} + 6 x^{3} + x^{2} - 24 x + 16

c^{2} + 11 c - 12

\frac{1}{10} + \frac{1}{12}

2 (3 w - 6) = 12

What is the answer to 2x+3(x-3)=6[2x-3(x-5)] ?
The answer to 2x+3(x-3)=6[2x-3(x-5)] is x=9
Solve for x: 2x+3(x-3)=6[2x-3(x-5)]
The solution is x=9