What are the solutions to the equation 9x^2-2x=2 ?

The solutions to the equation 9x^2-2x=2 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9

Find the zeros of 9x^2-2x=2

The zeros of 9x^2-2x=2 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9

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9 x^{2} - 2 x = 2

x = \frac{1 + 19}{9}, x = \frac{1 - 19}{9}

Decimal

x = 0.59543 \dots, x = - 0.37321 \dots

Solution steps

9 x^{2} - 2 x = 2

Move

2

to the left side

9 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 2) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 9} : \frac{1 + 19}{9}

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 9} : \frac{1 - 19}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 19}{9}, x = \frac{1 - 19}{9}

x^{2} + p x + q x + pq

13 < 14 (x + 1) < - 9

9 \cdot 81

2 x^{2} - 88 = 0

x^{2} \cdot x^{\frac{3}{2}}

What are the solutions to the equation 9x^2-2x=2 ?
The solutions to the equation 9x^2-2x=2 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9
Find the zeros of 9x^2-2x=2
The zeros of 9x^2-2x=2 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9