What are the solutions to the equation 8x^2-48x=0 ?

The solutions to the equation 8x^2-48x=0 are x=6,x=0

Find the zeros of 8x^2-48x=0

The zeros of 8x^2-48x=0 are x=6,x=0

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8 x^{2} - 48 x = 0

x = 6, x = 0

Solution steps

8 x^{2} - 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 48)^{2} - 4 \cdot 8 \cdot 0 = 48

x_{1, 2} = \frac{- ( - 48 ) \pm 48}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 48}{2 \cdot 8}, x_{2} = \frac{- ( - 48 ) - 48}{2 \cdot 8}

x = \frac{- ( - 48 ) + 48}{2 \cdot 8} : 6

x = \frac{- ( - 48 ) - 48}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

\frac{4 x + 5}{6} = \frac{7}{2}

123 \cdot 2

\frac{1}{1 - x} \leq \frac{1}{1 - x ^{2}}

\frac{( 4 - 0.5 ) ^{3} - 64}{- 0.5}

e^{5 l n (2)}

What are the solutions to the equation 8x^2-48x=0 ?
The solutions to the equation 8x^2-48x=0 are x=6,x=0
Find the zeros of 8x^2-48x=0
The zeros of 8x^2-48x=0 are x=6,x=0