What are the solutions to the equation (γ^2+γ+1)=0 ?

The solutions to the equation (γ^2+γ+1)=0 are γ=-1/2+i(sqrt(3))/2 ,γ=-1/2-i(sqrt(3))/2

Find the zeros of (γ^2+γ+1)=0

The zeros of (γ^2+γ+1)=0 are γ=-1/2+i(sqrt(3))/2 ,γ=-1/2-i(sqrt(3))/2

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(γ^{2} + γ + 1) = 0

γ = - \frac{1}{2} + i \frac{3}{2}, γ = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(γ^{2} + γ + 1) = 0

Refine

γ^{2} + γ + 1 = 0

Solve with the quadratic formula

γ_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

γ_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

γ_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, γ_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

γ = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

γ = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

γ = - \frac{1}{2} + i \frac{3}{2}, γ = - \frac{1}{2} - i \frac{3}{2}

3 x^{2} + 19 x = - 6

- 5 n^{2} + 4 n - 6 = 0

3 x^{2} - 4 x + 2 = 0

2^{k} \geq 30

∣ 5 x - 3 ∣ < 12

What are the solutions to the equation (γ^2+γ+1)=0 ?
The solutions to the equation (γ^2+γ+1)=0 are γ=-1/2+i(sqrt(3))/2 ,γ=-1/2-i(sqrt(3))/2
Find the zeros of (γ^2+γ+1)=0
The zeros of (γ^2+γ+1)=0 are γ=-1/2+i(sqrt(3))/2 ,γ=-1/2-i(sqrt(3))/2