What are the solutions to the equation 14x^2-x=3 ?

The solutions to the equation 14x^2-x=3 are x= 1/2 ,x=-3/7

Find the zeros of 14x^2-x=3

The zeros of 14x^2-x=3 are x= 1/2 ,x=-3/7

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14 x^{2} - x = 3

x = \frac{1}{2}, x = - \frac{3}{7}

Decimal Notation

x = 0.5, x = - 0.42857 \dots

Solution steps

14 x^{2} - x = 3

Move

3

to the left side

14 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 14 ( - 3 )}{2 \cdot 14}

(- 1)^{2} - 4 \cdot 14 (- 3) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 14}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 14}

x = \frac{- ( - 1 ) + 13}{2 \cdot 14} : \frac{1}{2}

x = \frac{- ( - 1 ) - 13}{2 \cdot 14} : - \frac{3}{7}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{3}{7}

2 x^{2} + 19 x + 35

\frac{2}{3 + i}

10 \cdot 7

(9^{2})^{5}

35 - \frac{x}{3} = \frac{x}{4}

What are the solutions to the equation 14x^2-x=3 ?
The solutions to the equation 14x^2-x=3 are x= 1/2 ,x=-3/7
Find the zeros of 14x^2-x=3
The zeros of 14x^2-x=3 are x= 1/2 ,x=-3/7